A vertical cut is to be made in saturated clay with c - 15 kN-m2-0- and - 20 kN-m3- What is the theoretical depth to which the clay can be excavated without side collapse-

The critical (theoretical) depth of vertical cut in a cohesive soil is given by H_c=4Cγ√(K_a) K_a=1 sinϕ1+sinϕ=1 sin0^∘1+sin0^∘=1 ∴ H_c=4× 1520×√(1)=3 m ...

You visited us 4 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Other

Foundation Engineering

Active Pressure -V

A vertical cu...

Question

A vertical cut is to be made in saturated clay with $c = 15 k N / m^{2}, ϕ = 0^{\circ},$ and $γ = 20 k N / m^{3} .$ What is the theoretical depth to which the clay can be excavated without side collapse?

6 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.5 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 3 m
The critical (theoretical) depth of vertical cut in a cohesive soil is given by
$H_{c} = \frac{4 C}{γ \sqrt{K_{a}}} K_{a} = \frac{1 - sin ϕ}{1 + sin ϕ} = \frac{1 - sin 0^{\circ}}{1 + sin 0^{\circ}} = 1 ∴ H_{c} = \frac{4 \times 15}{20 \times \sqrt{1}} = 3 m$

Suggest Corrections

Similar questions

Q. A vertical cut is made in a clay deposit having unit weight

19.5 k N / m^{3}

. The unconfined compressive strength is

50 k N / m^{2}

. What will be the maximum height of cut which can be temporarily supported? (Taylor stability number = 0.317)

Q. A

40^{\circ}

slope is excavated to a depth of 10 m in a deep layer of saturated clay of unit weight

20 k N / m^{3}

, if the relevant shear strength parameters are

C_{u} = 72 k N / m^{2}

and

ϕ_{u} = 0

. The Taylor's stability coefficient for

ϕ_{u} = 0

and

40^{\circ}

slope is 0.18. The factor of safety of the load is

Q. A rigid retaining wall of 6 m height has a saturated backfill of soft clay soil. What is the critical height when the properties of the clay soil are

γ_{s a t} = 17.56 k N / m^{3}

and cohesion

c = 18 k N / m^{2}

Q. An unsupported excavation is made to the maximum possible depth in a clay soil having

γ_{t}

18 k N / m^{3}

C = 100 k N / m^{2}

ϕ = 30^{\circ}

. The active earth pressure, according to Rankine's theory, at the base level of the excavation is

Q. A layer of clay of thickness 12.5 m is underlain by sand. The

γ_{s a t}

of the clay is 18.5

k N / m^{3}

. When the depth of an open trench excavated in the clay reached 8 m, the bottom cracked and the water started entering the trench from below. The height to which water would have risen from the top of sand in a bore hole if it was drilled into sand prior to the excavation is (

T a k e γ_{w} = 10 k N / m^{3}

Join BYJU'S Learning Program

A vertical cut is to be made in saturated clay with c=15 kN/m2,ϕ=0∘, and γ=20 kN/m3. What is the theoretical depth to which the clay can be excavated without side collapse?

The correct option is D 3 mThe critical (theoretical) depth of vertical cut in a cohesive soil is given by Hc=4Cγ√KaKa=1−sinϕ1+sinϕ=1−sin0∘1+sin0∘=1∴Hc=4×1520×√1=3 m

A vertical cut is to be made in saturated clay with $c = 15 k N / m^{2}, ϕ = 0^{\circ},$ and $γ = 20 k N / m^{3} .$ What is the theoretical depth to which the clay can be excavated without side collapse?

The correct option is D 3 m
The critical (theoretical) depth of vertical cut in a cohesive soil is given by
$H_{c} = \frac{4 C}{γ \sqrt{K_{a}}} K_{a} = \frac{1 - sin ϕ}{1 + sin ϕ} = \frac{1 - sin 0^{\circ}}{1 + sin 0^{\circ}} = 1 ∴ H_{c} = \frac{4 \times 15}{20 \times \sqrt{1}} = 3 m$