A vertical electric field of magnitude 4×105N/C just prevents a water droplet of mass 1×10−4kg from falling. Find the charge on the droplet.
A
1.5×10−9C
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B
2.5×10−9C
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C
3.5×10−9C
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D
4.5×10−9C
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Solution
The correct option is A1.5×10−9C
For charge to stay in equilibrium electrostatic force should balanced the gravity.
Hence, qE=mg ⇒q=mgE ⇒q=1×10−4×104×105 ⇒q=2.5×10−9C