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Question

The electric field strength in NC1 that us required to just prevent a water drop carrying a charge 1.6×1019C from falling under gravity is: (g=9.8ms2, mass of water drop=0.0016g)

A
9.8×1016
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B
9.8×1016
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C
9.8×1013
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D
9.8×1013
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E
9.8×1010
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Solution

The correct option is C 9.8×1013
Charge on drop q=16×1019C
Mass of the drop m=0.0016g
m=16×104g
m=16×107 kg
g=9.8m/s2
In balance position,
mg=qE
where, E is electric field strength.
E=mgq=16×107×9.816×1019
E=9.8×1013N/C.
722732_671279_ans_a9a0e49276244d91b2036752f8160660.jpg

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