A vertical ray of light strikes the horizontal surface of some water:

(a) What is the angle of incidence?
(b) What is the angle of refraction?

Open in App

Solution

(a) Angle of incidence is $0^{0}$ because light ray is travelling along the normal and angle of incidence is the angle between the light ray and the normal.
(b) If the incident ray falls normally on the surface, no bending of light ray takes place. So, the angle of refraction is also $0^{0}$ .

Suggest Corrections

Similar questions

Q. A vertical ray of light strikes the horizontal surface of water.What is the angle of refraction?

Q. A ray of light traveling in air strikes the water surface at an angle of

40^{o}

. What will be the refractive index of if angle refraction is

29^{o}

A ray of light strikes a plane mirror such that its angle of incidence is $30^{\circ}$ . What angle does the reflected ray make with the mirror surface?

Q. A horizontal ray of light passes through a prism of index of refraction

μ = 1.50

& apex angle

4^{\circ}

and then strikes a vertical mirror, as shown in the figure. Through what angle must the mirror be rotated if after reflection the ray is to be horizontal?

What is meant by the 'angle of incidence' and the 'angle of refraction' for a ray of light ? Draw a labelled ray diagram to show the angle of incidence and the angle of refraction for a refracted ray of light.

Join BYJU'S Learning Program

A vertical ray of light strikes the horizontal surface of some water: (a) What is the angle of incidence? (b) What is the angle of refraction?

(a) Angle of incidence is 00 because light ray is travelling along the normal and angle of incidence is the angle between the light ray and the normal. (b) If the incident ray falls normally on the surface, no bending of light ray takes place. So, the angle of refraction is also 00.

A vertical ray of light strikes the horizontal surface of some water:

(a) What is the angle of incidence?
(b) What is the angle of refraction?

(a) Angle of incidence is $0^{0}$ because light ray is travelling along the normal and angle of incidence is the angle between the light ray and the normal.
(b) If the incident ray falls normally on the surface, no bending of light ray takes place. So, the angle of refraction is also $0^{0}$ .