A very long straight wire carries a current I. At the instant when a charge +Q at point P has velocity $\to V$ , as shown, the force on the charge is

Along ox

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Opposite to oy

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Along oy

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Opposite to ox

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Solution

The correct option is B Along oy
$\to F = q e \to v \times \to B j = q v B e^i \times (-^k) j = q v B^j$
$\Rightarrow$ force on the charge is along oy

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A very long straight wire carries a current I. At the instant when a charge +Q at point P has velocity →V, as shown, the force on the charge is

The correct option is B Along oy→F=qe→v×→Bj=qvBe^i×(−^k)j=qvB^j⇒ force on the charge is along oy

A very long straight wire carries a current I. At the instant when a charge +Q at point P has velocity $\to V$ , as shown, the force on the charge is

The correct option is B Along oy
$\to F = q e \to v \times \to B j = q v B e^i \times (-^k) j = q v B^j$
$\Rightarrow$ force on the charge is along oy