Question

A very long wire carrying a current $I=5.0A$ is bent a right angles. Find the magnetic induction at a point lying on a perpendicular to the wire, drawn through the point of bending, at a distance $l=35cm$ from it.

Answer 1

the magnetic field due to the first half wire is finite the magnetic field due to the second half is zero the magnetic field at a point $p$

$B=\frac{{\mu }_{o}I}{4\pi d}\{sin\alpha +sin\beta \}=\frac{{10}^{-17}\times 5}{35\times {10}^{-2}}\times \{sin{90}^{\circ }+sin{0}^{\circ }\}$

$B=\frac{1}{7}\times {10}^{-5}=0.143\times {10}^{-7}T$