A vessel containing 10 litre of air under a pressure of 1 MPa is connected to a 4 litre empty vessel. The final air pressure in the vessel assuming that the process is isothermal.

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Solution

In isothermal process-

$P V = c o n s t a n t$

$⟹ P_{2} V_{2} = P_{1} V_{1}$

$⟹ P_{2} = \frac{P_{1} V_{1}}{V_{2}}$

$⟹ P_{2} = \frac{1 M P a \times 10}{14}$

$⟹ P_{2} = 0.714 M P a$

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A vessel containing 10 litre of air under a pressure of 1 MPa is connected to a 4 litre empty vessel. The final air pressure in the vessel assuming that the process is isothermal.

In isothermal process-PV=constant⟹P2V2=P1V1⟹P2=P1V1V2⟹P2=1MPa×1014⟹P2=0.714MPa

In isothermal process-

$P V = c o n s t a n t$

$⟹ P_{2} V_{2} = P_{1} V_{1}$

$⟹ P_{2} = \frac{P_{1} V_{1}}{V_{2}}$

$⟹ P_{2} = \frac{1 M P a \times 10}{14}$

$⟹ P_{2} = 0.714 M P a$