A vessel contains $1.6$ g of dioxygen at STP ( $273.15$ K, $1$ atm pressure). The gas is now transferred to another vessel at constant temperature, where pressure becomes half of the original pressure. The volume of the new vessel is:

2.24 L

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22.4 L

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11.2 L

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1.12 L

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Solution

The correct option is A 2.24 L
$1.6$ g of oxygen corresponds to $\frac{1.6}{32} = 0.05$ moles.
It occupies a volume of $22.4 \times 0.05 = 1.12 L$ at STP.
When the pressure is reduced to half, the volume is doubled.
The new volume is $2 \times 1.12 = 2.24 L$ .

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A vessel contains 1.6 g of dioxygen at STP (273.15K, 1 atm pressure). The gas is now transferred to another vessel at constant temperature, where pressure becomes half of the original pressure. The volume of the new vessel is:

The correct option is A 2.24 L1.6 g of oxygen corresponds to 1.632=0.05 moles.It occupies a volume of 22.4×0.05=1.12 L at STP.When the pressure is reduced to half, the volume is doubled.The new volume is 2×1.12=2.24 L.

A vessel contains $1.6$ g of dioxygen at STP ( $273.15$ K, $1$ atm pressure). The gas is now transferred to another vessel at constant temperature, where pressure becomes half of the original pressure. The volume of the new vessel is:

The correct option is A 2.24 L
$1.6$ g of oxygen corresponds to $\frac{1.6}{32} = 0.05$ moles.
It occupies a volume of $22.4 \times 0.05 = 1.12 L$ at STP.
When the pressure is reduced to half, the volume is doubled.
The new volume is $2 \times 1.12 = 2.24 L$ .