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Question

A vessel contains 100 litres of a liquid X. Heat is supplied to the liquid at a constant pressure of 1 atm in such a fashion that heat given is equal to the change in enthalpy of the system. The volume of the liquid increases by 2 litres. If 202.6 joules of heat were supplied, then the values of U and H would have been:
[U=change in internal energy, H change in enthalpy]

A
U=0, H=0
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B
U=+202.6 J, H=+202.6 J
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C
U=202.6 J, H=202.6 J
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D
U=0, H=+202.6 J
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Solution

The correct option is D U=0, H=+202.6 J
H=heat given. And the process is given to be isobaric.
Therefore
H=q=+202.6 J
And, w=Pext(V)=1×2 litre. atm×101.3=202.6 J
Hence, U=q+w=0

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