A vessel contains a mixture consisting of m1=7kg of nitrogen (M1=28) and m2=11g of carbon dioixide (M2=44) at temeprature T=300K and pressure P0=1atm. The density of the mixture is:
Let V is the volume of the vessel.
Now, let p1 and p2 be the partial pressure, then using gas law:
p1V=m1M1RT
p2V=m2M2RT, p0=p1+p2
p0=(m1M1+m2M2)RTV
V=(m1M1+m2M2)RTp0
∵ρmix=(m1+m2)V
ρmix=(m1+m2)M1M2(m1M2+m2M1)×p0RT
Substituting values,
ρmix=(7+11)×28×44×10−3(7×44+11×28))×1058.3×300
=1.446 per litre
Option A is correct.