A vessel contains helium, which expands at constant pressure when 15 kJ of heat is supplied to it. What will be the variation of the internal energy of the gas? (in kJ)
A
7
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B
8
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C
6
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D
9
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Solution
The correct option is D 9 Helium is monoatomic.
Hence, γ=Cp/Cv=5/3 At constant pressure, heat supplied =ΔQ=nCpΔT=15kJ Internal energy change =ΔU=nCvΔT=nCpΔT/γ=35×15kJ=9kJ