Question

A vessel contains $N_2{O}_4$ & $N{O}_2$ in 2:3 molar ratio at 10 atm under equilibrium. now $K_p$ for $N_2{O}_4\rightleftharpoons 2N{O}_2$ is:

• A. $9at{m}^{-1}$
• B. $9atm$
• C. $4.5at{m}^2$
• D. $10atm$

Answer 1

Answer: (B)

$9atm$

$N_2{O}_4$ and $N{O}_2$ in $2:3$ molar ratio $al=10$ atm

$\therefore$ Pressure of $N_2{O}_4=4$ atm

Pressure of $N{O}_2=6$ atm

$N_2{O}_4\rightleftharpoons 2N{O}_2$

$K_p=\frac{P_{{N{O}_2}^2}}{P_{N_2{O}_4}}=\frac{6^2}{4}=9$ atm.