A vessel has 6g of hydrogen at pressure P and temperature 500K. A small hole is made in it so that hydrogen leaks out. How much hydrogen leaks out if the final pressure is P/2 and temperature falls to 300K?
A
2g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D1g Let M be molar mass of gas We know, PV=nRT n= no. of mole =mM; where m= mass of gas. ⇒PV=mMRT Initially, PV=6MR×500 ...(i) Finally, P2×V=6−xMR×300 ...(ii) where x is the mass of gas leaked out. ∴ From eqn (i) and (ii), ⇒2=66−x×53 ⇒x=1g