A vessel is filled with a mixture of oxygen and nitrogen. A what ratio of partial pressures will the mass of gases be identical?

P (O_{2}) = 0.785 P (N_{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

P (O_{2}) = 8.75 P (N_{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

P (O_{2}) = 11.4 P (N_{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

P (O_{2}) = 0.875 P (N_{2})

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $P (O_{2}) = 0.875 P (N_{2})$
$P V = n R T$
$P V = \frac{w}{m} R T$
$P_{O_{2}} V = \frac{w}{32} R T$
$P_{N_{2}} V = \frac{w}{28} R T$
$\frac{P_{O_{2}}}{P_{N_{2}}} = \frac{28}{32}$
$P_{O_{2}} = 0.875 P_{N_{2}}$ .

Suggest Corrections

Similar questions

Q. A neon-dioxygen mixture contains

70.6 g

dioxygen and

167.5 g

neon. If the pressure of the mixture of gases in the cylinder is 25 bar, what is the partial pressure of dioxygen and neon in the mixture?

Q. A vessel is filled with a mixture of oxygen and nitrogen. At what ratio of partial pressures will the mass of gases be identical?

On a humid summer day, the partial pressure of water in the atmosphere is 18 mm Hg. The barometric pressure on this day is as high as 766 mm Hg, Calculate the partial pressures of nitrogen and oxygen if 78.0% of the dry atmosphere is composed of nitrogen molecules and 21.0% of oxygen? (1% of the dry atmosphere is composed of all other gases)

Q. Fill in the blanks with approriate words.
Alveolar

P O_{2}

is .......... than the venous

P O_{2}

while arterial

P O_{2}

is .......... than the alveolar

P O_{2}

Q. A vessel is filled with a mixture of oxygen and nitrogen. At what ratio of partial pressure will the mass of the gases be identical?

Join BYJU'S Learning Program

A vessel is filled with a mixture of oxygen and nitrogen. A what ratio of partial pressures will the mass of gases be identical?

The correct option is D P(O2)=0.875P(N2)PV=nRTPV=wmRTPO2V=w32RTPN2V=w28RTPO2PN2=2832PO2=0.875PN2.

The correct option is D $P (O_{2}) = 0.875 P (N_{2})$
$P V = n R T$
$P V = \frac{w}{m} R T$
$P_{O_{2}} V = \frac{w}{32} R T$
$P_{N_{2}} V = \frac{w}{28} R T$
$\frac{P_{O_{2}}}{P_{N_{2}}} = \frac{28}{32}$
$P_{O_{2}} = 0.875 P_{N_{2}}$ .