On a humid summer day, the partial pressure of water in the atmosphere is 18 mm Hg. The barometric pressure on this day is as high as 766 mm Hg, Calculate the partial pressures of nitrogen and oxygen if 78.0% of the dry atmosphere is composed of nitrogen molecules and 21.0% of oxygen? (1% of the dry atmosphere is composed of all other gases)

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Solution

The correct option is D

The pressure of dry atmosphere is given as $P_{d r y a t m o s p h e r e} = P_{t o t a l} - P_{H_{2} O}$ = 766 – 18 = 748 mm Hg

The pressure of nitrogen and oxygen gases are calculated as follows:-

$P_{N_{2}} = \frac{78}{100} \times 748$ = 583 mm Hg

$P_{O_{2}} = \frac{21}{100} \times 748$ = 157 mm Hg

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The correct option is D The pressure of dry atmosphere is given as Pdry atmosphere=Ptotal–PH2O = 766 – 18 = 748 mm Hg The pressure of nitrogen and oxygen gases are calculated as follows:- PN2=78100×748 = 583 mm Hg PO2=21100×748 = 157 mm Hg