A vessel of $120 c m^{3}$ contains a certain mass of a gas at $20^{\circ} C$ and $750 t o r r$ pressure. The gas was transferred to a vessel of volume $180 c m^{3}$ . Calculate the pressure of he gas at the same temperature.

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Solution

Applying Boyle's law.
$P_{1} V_{1} = P_{2} V_{2}$
= $120 \times 750 = 180 \times P_{2}$
= $P_{2} = 500 t o r r$

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A vessel of 120 cm3 contains a certain mass of a gas at 20∘C and 750 torr pressure. The gas was transferred to a vessel of volume 180 cm3. Calculate the pressure of he gas at the same temperature.

Applying Boyle's law.P1V1=P2V2= 120×750=180×P2= P2=500 torr

A vessel of $120 c m^{3}$ contains a certain mass of a gas at $20^{\circ} C$ and $750 t o r r$ pressure. The gas was transferred to a vessel of volume $180 c m^{3}$ . Calculate the pressure of he gas at the same temperature.

Applying Boyle's law.
$P_{1} V_{1} = P_{2} V_{2}$
= $120 \times 750 = 180 \times P_{2}$
= $P_{2} = 500 t o r r$