A vessel of volume $0.3 m^{3}$ contains Helium at $20.0$ . The average kinetic energy per molecule for the gas is:

6.07 \times 10^{- 21} J

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7.3 \times 10^{3} J

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14.6 \times 10^{3} J

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12.14 \times 10^{- 21} J

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Solution

The correct option is A $6.07 \times 10^{- 21} J$
Given temperature of gas $= 20 ° C$
$= 293 K$
$\Rightarrow$ Average translational kinetic energy $= \frac{3}{2} K T$
$= \frac{3}{2} \times 1.38 \times 10^{- 23} \times 293$
$= 6.07 \times 10^{- 21} J$
Hence, the answer is $6.07 \times 10^{- 21} J .$

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