Question

A village, having a population of 4000, requires 150 litres water per head per day. It has a tank which is 20 m long, 15 m broad and 6 m high. For how many days will the water of this tank last?

Answer 1

$$\begin{gathered} \mathrm{A}\mathrm{village}\mathrm{has}\mathrm{population}\mathrm{of}4000\mathrm{and}\mathrm{every}\mathrm{person}\mathrm{needs}150\mathrm{L}\mathrm{of}\mathrm{water}\mathrm{a}\mathrm{day}. \\ \mathrm{So},\mathrm{the}\mathrm{total}\mathrm{requirement}\mathrm{of}\mathrm{water}\mathrm{in}\mathrm{a}\mathrm{day}=4000\times 150\mathrm{L}=600000\mathrm{L} \\ \mathrm{Also},\mathrm{it}\mathrm{is}\mathrm{given}\mathrm{that}\mathrm{the}\mathrm{length}\mathrm{of}\mathrm{the}\mathrm{water}\mathrm{tank}\mathrm{is}20\mathrm{m}. \\ \mathrm{Breadth}=15\mathrm{m} \\ \mathrm{Height}=6\mathrm{m} \\ \mathrm{Volume}\mathrm{of}\mathrm{the}\mathrm{tank}=\mathrm{length}\times \mathrm{breadth}\times \mathrm{height}=20\times 15\times 6=1800{\mathrm{m}}^3 \\ \mathrm{Now},\mathit{}1{\mathrm{m}}^3=1000\mathrm{L} \\ \mathrm{i}.\mathrm{e}.,1800{\mathrm{m}}^3=1800\times 1000\mathrm{L}=1800000\mathrm{L} \\ \mathrm{The}\mathrm{tank}\mathrm{has}1800000\mathrm{L}\mathrm{of}\mathrm{water}\mathrm{in}\mathrm{it}\mathrm{and}\mathrm{the}\mathrm{whole}\mathrm{village}\mathrm{need}600000\mathrm{L}\mathrm{per}\mathrm{day}. \\ \therefore \mathrm{The}\mathrm{water}\mathrm{in}\mathrm{the}\mathrm{tank}\mathrm{will}\mathrm{last}\mathrm{for}\frac{1800000}{600000}\mathrm{days},\mathrm{i}.\mathrm{e}.,3\mathrm{days}. \end{gathered}$$