Question

A voltage of 30 V is applied across a colour coded carbon resister with first, second and third rings of blue, black and yellow colours. What is the current flowing through the resistor?

Answer 1

Value of first digit (blue ring)=6
Value of second digit (black ring)=0
Multiplier (yellow ring)=${10}^4$

$\therefore$ Resistance , $R=60\times {10}^4\Omega ,voltage,V=30V$

Current $I=\frac{V}{R}=\frac{30}{60\times {10}^4}=0.5\times {10}^{-4}A=0.05m$