Question

A wall $9.68m$ long and $6.2m$ high is covered with rectangular tiles of size $44cm$ by $20cm$. Find the total cost of the tiles at the rate of $Rs.18.50$ per tile.

Answer 1

Length of the wall $\left(l\right)=9.68m$

Height of the wall $\left(h\right)=6.2m$

Area of the wall $=l\times h=9.68m\times 6.2m=60.016m^2$

Lets convert the units $cm$ into $m$.

We know that, $1cm=\frac{1}{100}m$

$\Rightarrow$ $44cm=\frac{44}{100}m=0.44m$

$\Rightarrow$ $20cm=\frac{20}{100}m=0.2m$

Area of one tile $=0.44m\times 0.20m$ $=0.088m^2$

Number of tiles $=\frac{Areaofthewall}{Areaofonetile}=\frac{60.016}{0.088}=682$

Cost of $1$ tile $=Rs.18.50$

Cost of $682$ tiles

$=Rs.18.50\times 682=Rs.12617$