A wall is of the form of a trapezium with height 4 m and parallel sides being 3 m and 5 m. What is the cost of painting the wall, if the rate of painting is Rs. 25 per square metre?
A
Rs. 240
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B
Rs. 400
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C
Rs. 480
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D
Rs. 800
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Solution
The correct option is B Rs. 400
Given, height of trapezium =3 m, two sides length =3 m and =5 m.
Area of trapezium =side1+side22×height
Area of wall =12(5+3)×4
=12×8×4=16 sq. m
The rate of painting is Rs. 25 per square metre. Thus cost of painting for 16 sq. m is =16×25= Rs. 400.