Question

A water fountain on the ground sprinkles water in all directions around it. If the speed of water coming out of the fountain is v, then total area around the fountain that gets wet is ?

Answer 1

$$\begin{gathered} \mathrm{Maximum}\mathrm{range},\mathrm{R}=\frac{{\mathrm{v}}^2}{\mathrm{g}}=\mathrm{Radius}\mathrm{of}\mathrm{circle} \\ \mathrm{Total}\mathrm{area}\mathrm{around}\mathrm{the}\mathrm{fountain}\mathrm{that}\mathrm{gets}\mathrm{wet},\mathrm{A}={\mathrm{\pi R}}^2=\mathrm{\pi }[\frac{{\mathrm{v}}^2}{\mathrm{g}}{]}^2=\frac{{\mathrm{\pi v}}^4}{{\mathrm{g}}^2} \end{gathered}$$