A water sample contains 0.10 ppm of chloroform. How many molecules of chloroform will be present in 0.5 mL of this water?
A
4.18×10−5×NA
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B
4.18×10−6×NA
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C
4.18×10−10×NA
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D
4..18×10−9×NA
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Solution
The correct option is C4.18×10−10×NA 0.5 mL≡0.5 g of water 106 g of water contains 0.10 g CHCl3.
0.5 g of water contains 0.1106×0.5 g of CHCl3.
Number of moles of CHCl3 present in the sample, nCHCl3=0.1106×0.5119.5=4.18×10−10
Number of molecules of CHCl3 4.18×10−10×NA