A water treatment plant capacity, 1m3/s has filter boxes of dimension 6×10m. Loading rate to the filter is 120m3/day/m2. When two of the filters are out of service for back washing, the loading rate (in m3/d/m2) is
144
Open in App
Solution
The correct option is A 144 Total water filtered in a day
= 24×3600×1
=86400m3/day
Total surface area of filter required
=86400m3/day120m3/day/m2=720m2
Area of one filter = 6×10=60m2
Total no. of filter = 72060=12filters
If two filters are out of service no. of filters remain 12-2 = 10 filters
Total surface area of filter = 60×10=600m2
The new loading rate= 86400m3/day600m2 =144m3/day/m2