Question

A wave of frequency $1000Hz$ travels between $X$ and $Y$, a distance of $600m$ in $2$ seconds. The number of wavelengths there with in distance $XY$

• A. $3.3$
• B. $300$
• C. $180$
• D. $2000$

Answer 1

The correct option is D $2000$

$speed\left(v\right)$ $=$ $\frac{distance\left(s\right)}{time\left(t\right)}$

$\therefore s$ $=$ $v\times t$

$v$ $=$ $frequency\left(f\right)\times wavelength\left(\lambda \right)$

$\therefore s$ $=$ $f\times \lambda \times t$

$number$ $of$ $waves$ $=$ $\frac{s}{\lambda }$ $=$ $\frac{f\times \lambda \times t}{\lambda }=f\times t=1000\times 2=2000$

$The$ $number$ $of$ $waves$ $within$ $XY$ $is$ $2000$