Question

A wave of wave length $60m$, amplitude $A=0.2m$ is moving along positive X-axis with speed $v=360m/s$. Equation of wave will be

• A. $y=0.2\sin 2\pi (\frac{x}{60}-6t)$
• B. $y=0.2\sin \pi (6t-\frac{x}{60})$
• C. $y=0.2\sin 2\pi (6t+\frac{x}{60})$
• D. $y=0.2\sin \pi (6t+\frac{x}{60})$

Answer 1

Answer: (A)

$y=0.2\sin 2\pi (\frac{x}{60}-6t)$

wave length$=\lambda =60m$

Amplitude$=A=0.2m$

Velocity$=v=360m/s$

Equation of the wave is given by,

$y=Asin\left(2\pi \frac{(x-vt)}{\lambda }\right)$

putting the given values,

$\therefore y=0.2sin2\pi (\frac{x}{60}-\frac{360t}{60})$

$\therefore y=0.2sin2\pi (\frac{x}{60}-6t)$