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Question

A wave, y=2sin(πt+x+π6) is propagating on a stretched string fixed at one end. The equation of reflected wave can be given as

A
2sin (πtx+π6)
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B
3sin (πtx+π6)
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C
3sin (πtx+π6)
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D
2sin (πtx+π6)
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Solution

The correct option is A 2sin (πtx+π6)
As we know that, when reflection takes place from fixed end reflected wave has phase difference of π with respect to incident wave.
Also, direction of propagation of reflected wave is opposite to the incident wave.
Equation of reflected wave can be given as
yr=2sin (πtx+π6+π)
=2sin (πtx+π6)

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