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Question

A weak monobasic acid solution has a pH value of 5. If its molarity is 0.005 M, then the degree of ionisation of the acid is:

A
5×103
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B
2×103
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C
5×102
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D
2×102
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Solution

The correct option is B 2×103
Given that a weak monobasic acid (say HA) has a pH value of 5 and concentration of 0.005 M.
We know pH=log [H+]=5
Hence, [H+]=105
The ionisation reaction is as follows:
HA H++A
(1α)c αc αc
Here, α is the degree of ionisation and c is the concentration of an acid.
The relationship between degree of ionization and concentration is α=[H]+c
On substituting values in the above equation, we get
α=1050.005=2×103
Hence, the degree of ionisation is 2×103.

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