A weight lifter 300 kg from the ground to a height of 2 meter in 33 seconds. The average power generated by him is:-

5880 Watt

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4410 watt

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2205 watt

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1960 Watt

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Solution

The correct option is D 1960 Watt
Power = $W / t$
where W is work done and t is time taken to complete work.
$W = m g h$
and $t = 3 s$ here
putting values:
$P = \frac{w o r k d o n e}{T i m e} = \frac{m g h}{t} = \frac{300 \times 9.8 \times 2}{3} = 1960 W$

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