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Standard XII

Physics

Thermal Expansion

A weight lift...

Question

A weight lifter lifted a load of $200 k g$ to a height of $2.5 m$ in $5 s$ . calculate the work done by weight lifter on load. Take $g = 10 m / s^{- 2}$

500 J

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50 J

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5000 k J

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5 k J

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Solution

The correct option is B $5 k J$
$W o r k = F \times S \times cos θ$ .Given mass = $200 K g f$ and distance is $2.5 m$ and angle is 0 degree and we know that $c o s 0 = 1.$
We know that
$F = m \times g = 200 \times 10 = 2000 N f$
Hence,
$W = 2000 \times 2.5 = 5000 J$ .

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Similar questions

A weight lifter lifted a load of 200 kgf to a height of 2.5 m in 5 s. Calculate :(i) the work done, and (ii) the power developed by him.Take g=10 N $k g^{- 1}$ .

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A weight lifter lifted a load of 200kg to a height of 2.5m in 5s. calculate the work done by weight lifter on load. Take g=10m/s−2

The correct option is B 5kJWork=F×S×cosθ.Given mass = 200Kgf and distance is 2.5m and angle is 0 degree and we know that cos0=1.We know that F=m×g=200×10=2000NfHence, W=2000×2.5=5000J.

A weight lifter lifted a load of $200 k g$ to a height of $2.5 m$ in $5 s$ . calculate the work done by weight lifter on load. Take $g = 10 m / s^{- 2}$

The correct option is B $5 k J$
$W o r k = F \times S \times cos θ$ .Given mass = $200 K g f$ and distance is $2.5 m$ and angle is 0 degree and we know that $c o s 0 = 1.$
We know that
$F = m \times g = 200 \times 10 = 2000 N f$
Hence,
$W = 2000 \times 2.5 = 5000 J$ .