A well of diameter 2 m is dug 14 m deep. The earth taken out of it is spread evenly all around it to a width of 5 m to form an embankment. Find the height of the embankment.
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Solution
Let h be the required height of the embankment.
The shape of the embankment will be like the shape of a cylinder of internal radius 1 m
and external radius (5 + 1) m = 6 m.
The volume of the embankment will be equal to the volume of the earth dug out from the well. Now, the volume of the earth dug out = volume of the cylindrical well
= π × 12 × 14 m3= 14 π m3
Also, the volume of the embankment = π(62 – 12) h cm3 = 35 π h m3
Hence, we have
35πh m3= 14π m3
h = 1435 = 0.4
Hence, the required height of the embankment = 0.4 m.