A when added to silica gives B. A and B are:

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Solution

The correct option is A

$H_{2} C O_{3 (a q)} + H_{2} O_{(l)} ⇌ H C O_{3 (a q)}^{⊖} + H_{3} O_{(a q)}^{⊖}$

$H C O_{3 (a q)}^{⊖} + H_{2} O_{(l)} ⇌ C O_{3 (a q)}^{2 -} + H_{3} O_{(a q)}^{⊖}$

Silica is readily attacked by HF, resulting in the formation of $S i F_{4}$ .

$S i O_{2} + 4 H F \to S i F_{4} + 2 H_{2} O$

$S i F_{4}$ thus formed dissolves in HF, forming hydroflurosilicic acid.

$S i F_{4} + 2 H F \to H_{2} S i F_{6}$

Due to the formation of $H_{2} S i F_{6}, S i O_{2}$ present in glass dissolves. Therefore, HF cannot be stored in glass bottles.

$4 H F + S i O_{2} \to H_{2} S i F_{4} + H_{2} O$

$↓ ↓$

$A B$

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