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Interstitial Compounds

A white cryst...

Question

A white crystalline solid give following chemical test: ' X'
(i) It liberates CO2 with $N a H C O_{3}$
(ii) It forms a coloured dye on diazotization and coupling with $β$ -Naphthol
(iii) With $B r_{2}$ water it forms white precipitate of 2, 4, 6 – tribromo aniline. ‘X’ can be identified as:

A

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B

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C

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D

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Solution

The correct option is B

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Similar questions

A white crystalline solid “X” gives following chemical tests:
(i) it liberates $C O_{2}$ with $N a H C O_{3}$
(ii) It forms a coloured dye on diazotisation and coupling with $β$ -napthol
(iii) With $B r_{2}$ water it forms white ppt of 2, 4, 6 – tribromo aniline.
Then “X” can be:

Q. A white crystalline solid

A

on dissolving in water forms a neutral solution. When solid

A

is heated with calcium hydroxide, it gives off colourless gas

B

having a sharp biting smell. The gas fumes very strongly in the air and turns red litmus blue. The aqueous solution of

A

on treating with lead acetate solution forms a white precipitate

C

. The precipitate is insoluble in all acids.
i) Name the anion present in solid

A

.
ii) Name the solid

A

and write its chemical formula.
iii) Name the white precipitate

C

.
iv) Write one chemical test for the identification of gas

B

.
v) Name the colourless gas

B

.

^{'} A^{'}

is treated with a freshly prepared ammonical silver nitrate solution, it gives bright silver mirror. The liquid forms a white crystalline soild on treatment with sodium hydrogensulphit. Liquid

^{'} B^{'}

also forms a white crystalline solid with sodium hydrogensulphite but it does not give test with ammoniacal silver nitrate. Which of the two liquids is aldehyde? Write the chemical equations of these reactions also.

Q. Assertion :Aniline on reaction with

{N a N O}_{2} / H C l

0^{o} C

followed by coupling with

β

naphthol gives a dark blue coloured precipitate. Reason: The colour of the compound formed in the reaction of aniline with

{N a N O}_{2} / H C l

0^{o} C

followed by coupling with

β

naphthol is due to extended conjugation.

A

has molecular formula

C_{7} H_{7} N O

. On treatment with

B r_{2}

K O H

A

B

which gives carbylamine test.

B

upon diazotization and coupling with phenol gives an azo dye.

A

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