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Preparations and Uses of Sodium Carbonate

A white cryst...

Question

A white crystalline solid “X” gives following chemical tests:

(i) it liberates $C O_{2} w i t h N a H C O_{3}$

(ii) It forms a coloured dye on diazotisation and coupling with $β$ - napthol

(iii) With $B r_{2}$ water it forms white ppt of 2, 4, 6 – tribromo aniline. Then "X" can be :

A

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B

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C

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D

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Solution

The correct option is B

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Similar questions

Q. A white crystalline solid give following chemical test: ' X'
(i) It liberates CO2 with

N a H C O_{3}

(ii) It forms a coloured dye on diazotization and coupling with

β

-Naphthol
(iii) With

B r_{2}

water it forms white precipitate of 2, 4, 6 – tribromo aniline. ‘X’ can be identified as:

^{'} A^{'}

is treated with a freshly prepared ammonical silver nitrate solution, it gives bright silver mirror. The liquid forms a white crystalline soild on treatment with sodium hydrogensulphit. Liquid

^{'} B^{'}

also forms a white crystalline solid with sodium hydrogensulphite but it does not give test with ammoniacal silver nitrate. Which of the two liquids is aldehyde? Write the chemical equations of these reactions also.

Q.
Statement I: Aniline on reaction with

N a N O_{2} / H C l

0^{o} C

followed by coupling with

β

-naphthol gives a dark blue coloured precipitate.
Statement II: The colour of the compound formed in the reaction of aniline with

N a N O_{2} / H C l

0^{o} C

followed by coupling with

β

X

has molecular formula

C_{7} H_{7} N O

. On treatment with

{B r}_{2}

K O H

X

Y

. The later gives carbylamine test.

Y

upon diazotisation and coupling with phenol gives an azo dye. Thus,

X

Q. Assertion :Aniline on reaction with

{N a N O}_{2} / H C l

0^{o} C

followed by coupling with

β

naphthol gives a dark blue coloured precipitate. Reason: The colour of the compound formed in the reaction of aniline with

{N a N O}_{2} / H C l

0^{o} C

followed by coupling with

β

naphthol is due to extended conjugation.

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Preparations and Uses of Sodium Carbonate

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