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Borax

A white solid...

Question

A white solid forms Rinmann's green in the charcoal cavity test in an oxidising flame. On treatment with dilute $H_{2} S O_{4}$ , this solid produces a gas that turns an acidified dichromate paper green and lead acetate paper black. The white solid is:

A

P b S

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B

Z n S O_{3}

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C

Z n S

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D

N a_{2} S

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Solution

The correct option is B $Z n S$
Compound is ZnS.
Reactions:
$Z n S + H_{2} S O_{4} \to Z n S O_{4} + H_{2} S$
$8 K M N O_{4} + 7 H_{2} S O_{4} + 5 H_{2} S \to 4 K_{2} S O_{4} + 8 M n S O_{4} + 12 H_{2} O$

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