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Question

A wire extends by 1 mm when a force is applied. Double the force is applied to another wire of same material and length but half the radius of cross section. The elongation of the wire in mm will be


  1. 1
  2. 4
  3. 2
  4. 8


Solution

The correct option is D 8

Y=FlA lor l Fr2

or  l2 l1=F2F1× r21r22

or  l2 l1=2× 2× 2=8

or  l2=8 l1=8× 1=8 mm

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