Question

A wire has a resistance of $6\Omega$. It is cut into two parts and both half values are connected in parallel. The new resistance is

• A. $6\Omega$
• B. $3\Omega$
• C. $12\Omega$
• D. $1.5\Omega$

Answer 1

The correct option is D $1.5\Omega$

A wire has a resistance of $6\Omega$. It is cut into two parts and both half values are connected in parallel combination.

$R_1=R_2=\frac{6\Omega }{2}=3\Omega$

In parallel combination,

$\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}$

$\frac{1}{R_{eq}}=\frac{1}{3}+\frac{1}{3}=\frac{2}{3}$

$R_{eq}=\frac{3}{2}=1.5\Omega$

The correct option is D.