A wire is cut into several small pieces . Each small is bent into a square of side 3 CM. If the total area of small square is 72 square CM. What was the original length of wire

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Solution

Side length of small squares = 3 cm
Therefore area of 1 small square = 3 x 3 = 9 cm²
Given total Area = 72 cm²
Therefore no of small squares = 72/ 9 = 8 sqaures

Perimeter of one small square = 4a = 4 x 3 = 12 cm

Therefore total length = 12 x 8 = 96 cm

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A wire is cut into several small pieces . Each small is bent into a square of side 3 CM. If the total area of small square is 72 square CM. What was the original length of wire

Side length of small squares = 3 cm Therefore area of 1 small square = 3 x 3 = 9 cm² Given total Area = 72 cm² Therefore no of small squares = 72/ 9 = 8 sqaures Perimeter of one small square = 4a = 4 x 3 = 12 cm Therefore total length = 12 x 8 = 96 cm

Side length of small squares = 3 cm
Therefore area of 1 small square = 3 x 3 = 9 cm²
Given total Area = 72 cm²
Therefore no of small squares = 72/ 9 = 8 sqaures

Perimeter of one small square = 4a = 4 x 3 = 12 cm

Therefore total length = 12 x 8 = 96 cm