Question

A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the same wire is bent in the shape of a square, what will be the measure of each side. Also, find which side encloses more area?

Answer 1

We have,
Perimeter the of rectangle = 2(Length + Breadth)
= 2(40 cm + 22 cm) = 124 cm
It is given that the wire which was in the shape of a rectangle is now bent into a square.
Therefore, the perimeter of the square = Perimeter of the rectangle
=> Perimeter of the square = 124 cm
⇒ 4 x side = 124 cm
∴ Side = $\frac{124}{4}=31\mathrm{cm}$
Now,
Area of the rectangle = 40 cm x 22 cm = 880 cm²
Area of the square = (Side)² = (31 cm)² = 961 cm²
Therefore, the square-shaped wire encloses more area.