A wire of length 86cm is bent in form of a rectangle such that its length is 7cm more than its breadth.Find the length and breadth of the rectangle so formed.

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Solution

Total length of the wire
=86cm
Length(L)
=breadth(B)+7cm
L=B+7
Perimeter of the rectangle=86cm
Perimeter of the rectangle = 2(length+breadth)
=2(L+B)
Length=L,breadth=B
86=2(L+B)
86=2{(B+7)+B}
86=2*{2B+7}
86=4B+14
4B=86-14
4B=72
B=72/4
B=18
Breadth =18cm
Length =18+7=25cm

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A wire of length 86cm is bent in form of a rectangle such that its length is 7cm more than its breadth.Find the length and breadth of the rectangle so formed.

Total length of the wire =86cm Length(L) =breadth(B)+7cm L=B+7 Perimeter of the rectangle=86cm Perimeter of the rectangle = 2*(length+breadth) =2*(L+B) Length=L,breadth=B 86=2*(L+B) 86=2*{(B+7)+B} 86=2*{2B+7} 86=4B+14 4B=86-14 4B=72 B=72/4 B=18 Breadth =18cm Length =18+7=25cm

Total length of the wire
=86cm
Length(L)
=breadth(B)+7cm
L=B+7
Perimeter of the rectangle=86cm
Perimeter of the rectangle = 2(length+breadth)
=2(L+B)
Length=L,breadth=B
86=2(L+B)
86=2{(B+7)+B}
86=2*{2B+7}
86=4B+14
4B=86-14
4B=72
B=72/4
B=18
Breadth =18cm
Length =18+7=25cm