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Standard XI

Mathematics

Squaring an Inequality

A woman has m...

Question

A woman has m $$ 20$ notes and n $$ 50$ notes. The total amount of money in her possession cannot be less than $$ 800$ . Represent this as an inequality.

$20 m + 50 n < 800$

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$20 m + 50 n \leq 800$

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$20 m + 50 n > 800$

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$20 m + 50 n \geq 800$

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Solution

The correct option is D
$20 m + 50 n \geq 800$

Total value of m $$ 20$ notes and n $$ 50$ notes = 20m + 50 n
The least amount of money the woman can have in her possession is $$ 800$ .
Therefore, $20 m + 50 n \geq 800$
The correct choice is D.

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A woman has m $20 notes and n $50 notes. The total amount of money in her possession cannot be less than $800. Represent this as an inequality.

The correct option is D 20m+50n≥800 Total value of m $20 notes and n $50 notes = 20m + 50 n The least amount of money the woman can have in her possession is $800. Therefore, 20m+50n≥800 The correct choice is D.

A woman has m $$ 20$ notes and n $$ 50$ notes. The total amount of money in her possession cannot be less than $$ 800$ . Represent this as an inequality.

The correct option is D
$20 m + 50 n \geq 800$

Total value of m $$ 20$ notes and n $$ 50$ notes = 20m + 50 n
The least amount of money the woman can have in her possession is $$ 800$ .
Therefore, $20 m + 50 n \geq 800$
The correct choice is D.