A woman starts from her home at 9.00 am, walks with a speed of 5 km h¯¹ on a straight road up to her office 2.5 km away, stays at the office up to 5.00 pm, and returns home by an auto with a speed of 25 km h–1. Choose suitable scales and plot the x-t graph of her motion.
Given: The speed of the woman is 5 kmh -1 , the distance between the office and home is 2.5 km and the speed of auto is 25 kmh -1 .
The time taken in the first case is given as,
t 1 = d v 1
Where, the total distance is d , and the speed is v 1 and the time taken in the first case is t 1 .
By substituting the given values in the above formula, we get
t 1 = 2.5 5 = 0.5 hours = 30 min
The time taken in the second case is given as,
t 2 = d v 2
Where, the total distance is d and the speed is v 2 .
By substituting the given values in the above formula, we get
t 2 = 2.5 25 = 0.1 hours = 6 min
The above values can be observed from the below graph.
Given: The speed of the woman is
The time taken in the first case is given as,
Where, the total distance is
By substituting the given values in the above formula, we get
The time taken in the second case is given as,
Where, the total distance is
By substituting the given values in the above formula, we get
The above values can be observed from the below graph.
