1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A wooden block in the form of a uniform cylinder floats with one-third length above the water surface. A small chip of this block is cut and held at rest at the bottom of a container containing water to a height of 1 m and is then released. The time in which it will rise to the surface of water is (g=10 m/s2)

A
0.84 s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.63 s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
0.50 s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.98 s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is B 0.63 sSince two-thirds of the wooden block is immersed in water, its density =2ρ/3, where ρ is the density of water. Let the volume of the chip be V. Then its weight is (2/3)Vρg. The upthrust acting on it inside the water is Vρg. Hence, the unbalanced upward force is Vρg(1−2/3)=Vρg/3. Hence, its acceleration a in the upward direction is a=Vρg/3(2/3)Vρ=g2 If t is the required time, then 1=0+12at2=12g2t2 Hence, t2=4g=410=0.4 t=0.63 s

Suggest Corrections
2
Join BYJU'S Learning Program
Related Videos
Simple Harmonic Oscillation
PHYSICS
Watch in App
Join BYJU'S Learning Program