A wooden block of 1 kg rests on a smooth surface inclined 30- with horizontal- Find the components of the weight of the block perpendicular and parallel to the plane-

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Standard XII

Physics

Surface Tension

A wooden bloc...

Question

A wooden block of $1$ kg rests on a smooth surface inclined $30^{\circ}$ with horizontal. Find the components of the weight (of the block) perpendicular and parallel to the plane.

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Solution

Given mass of the wooden block $m = 1 k g$ and angle of inclination $θ = 30^{0}$
Thus the $⊥$ component of weight $= m g cos θ = 5 \sqrt{3}$
and the parallel component of the weight $m g sin θ = 5$ , where mass m=1 kg and g= 10 $m / s^{2}$

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A wooden block of 1 kg rests on a smooth surface inclined 30∘ with horizontal. Find the components of the weight (of the block) perpendicular and parallel to the plane.

Given mass of the wooden block m=1kg and angle of inclination θ=300Thus the ⊥ component of weight =mgcosθ=5√3and the parallel component of the weight mgsinθ=5, where mass m=1 kg and g= 10m/s2

A wooden block of $1$ kg rests on a smooth surface inclined $30^{\circ}$ with horizontal. Find the components of the weight (of the block) perpendicular and parallel to the plane.

Given mass of the wooden block $m = 1 k g$ and angle of inclination $θ = 30^{0}$
Thus the $⊥$ component of weight $= m g cos θ = 5 \sqrt{3}$
and the parallel component of the weight $m g sin θ = 5$ , where mass m=1 kg and g= 10 $m / s^{2}$