A wooden block of volume 1000cm2 is suspended from a spring balance. Its weight is 12 N in air. It is suspended in water such that half of the block is below the surface of water. The reading of spring balance is-
A
10 N
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B
9 N
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C
8 N
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D
7 N
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Solution
The correct option is B 7 N Volume submerged V=500cm3 Therefore weight of water displaced is 500gm=0.5kg Buoyant force applied by the water is F=0.5×10=5N Net weight is W=12−5=7N