A wooden block of volume $1000 c m^{2}$ is suspended from a spring balance. Its weight is 12 N in air. It is suspended in water such that half of the block is below the surface of water. The reading of spring balance is-

10 N

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9 N

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8 N

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7 N

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Solution

The correct option is B 7 N
Volume submerged $V = 500 c m^{3}$
Therefore weight of water displaced is $500 g m = 0.5 k g$
Buoyant force applied by the water is $F = 0.5 \times 10 = 5 N$
Net weight is $W = 12 - 5 = 7 N$

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A wooden block of volume 1000cm2 is suspended from a spring balance. Its weight is 12 N in air. It is suspended in water such that half of the block is below the surface of water. The reading of spring balance is-

The correct option is B 7 NVolume submerged V=500cm3Therefore weight of water displaced is 500gm=0.5kgBuoyant force applied by the water is F=0.5×10=5NNet weight is W=12−5=7N

A wooden block of volume $1000 c m^{2}$ is suspended from a spring balance. Its weight is 12 N in air. It is suspended in water such that half of the block is below the surface of water. The reading of spring balance is-

The correct option is B 7 N
Volume submerged $V = 500 c m^{3}$
Therefore weight of water displaced is $500 g m = 0.5 k g$
Buoyant force applied by the water is $F = 0.5 \times 10 = 5 N$
Net weight is $W = 12 - 5 = 7 N$