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Question

A wooden block of volume $$1000cm^{2}$$ is suspended from a spring balance. Its weight is 12 N in air. It is suspended in water such that half of the block is below the surface of water. The reading of spring balance is-


A
10 N
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B
9 N
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C
8 N
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D
7 N
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Solution

The correct option is B 7 N
Volume submerged $$V=500cm^3$$
Therefore weight of water displaced is $$500gm=0.5kg$$
Buoyant force applied by the water is $$F=0.5\times 10=5N$$
Net weight is $$W=12-5=7N$$

Physics

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