A wooden box is placed on the back part of lorry moving with an acceleration of 6ms-2- If -k - 0-5- the acceleration of the box relative to lorry in ms-2 is

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Standard XII

Chemistry

Longest Chain Rule

A wooden box ...

Question

A wooden box is placed on the back part of lorry moving with an acceleration of $6 m s^{- 2}$ . If $μ_{k} = 0.5$ , the acceleration of the box relative to lorry in $m s^{- 2}$ is

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Solution

The correct option is B 1.1
$a_{b o x} = a_{t r u c k} - μ_{k} . g$
$a_{b o x} = 6 - 0.5 g = 6 - 4.9 = 1.1 m s^{- 2}$

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A wooden box is placed on the back part of lorry moving with an acceleration of 6ms−2. If μk=0.5, the acceleration of the box relative to lorry in ms−2 is

The correct option is B 1.1abox=atruck−μk.gabox=6−0.5g=6−4.9=1.1 ms−2

A wooden box is placed on the back part of lorry moving with an acceleration of $6 m s^{- 2}$ . If $μ_{k} = 0.5$ , the acceleration of the box relative to lorry in $m s^{- 2}$ is

The correct option is B 1.1
$a_{b o x} = a_{t r u c k} - μ_{k} . g$
$a_{b o x} = 6 - 0.5 g = 6 - 4.9 = 1.1 m s^{- 2}$