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Standard VII

Mathematics

Partnership

A worker in a...

Question

A worker in a factory is paid $R s . x$ per hour for the normal work and double this rate for the overtime work. Find the total earning 'E' in rupees of a worker who works for $20$ hours out of which $y$ hours is the overtime.

x (20 - y) - x y

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x (20 - y) + x y

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x (20 - y) + 2 x y

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x (20 - y) - 2 x y

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Solution

The correct option is C $x (20 - y) + 2 x y$
Normal working rate = $R s . x$ and Overtime working rate = $R s . 2 x$
Total no. of working hours = $20$
Overtime working hrs = $y$
$∴$ Normal working hrs = $(20 - y)$ hrs
Total earned $E = (20 - y) x + 2 x (y)$ = $x (20 - y) + 2 x y$

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A worker in a factory is paid Rs.x per hour for the normal work and double this rate for the overtime work. Find the total earning 'E' in rupees of a worker who works for 20 hours out of which y hours is the overtime.

The correct option is C x(20−y)+2xyNormal working rate = Rs.x and Overtime working rate = Rs.2x Total no. of working hours = 20Overtime working hrs = y∴ Normal working hrs = (20−y) hrsTotal earned E=(20−y)x+2x(y) = x(20−y)+2xy

A worker in a factory is paid $R s . x$ per hour for the normal work and double this rate for the overtime work. Find the total earning 'E' in rupees of a worker who works for $20$ hours out of which $y$ hours is the overtime.

The correct option is C $x (20 - y) + 2 x y$
Normal working rate = $R s . x$ and Overtime working rate = $R s . 2 x$
Total no. of working hours = $20$
Overtime working hrs = $y$
$∴$ Normal working hrs = $(20 - y)$ hrs
Total earned $E = (20 - y) x + 2 x (y)$ = $x (20 - y) + 2 x y$