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Reduction of Carboxylic Acids

AC6H5-CHOBA a...

Question

$A H_{2} - ------ \to P d - B a S O_{4} C_{6} H_{5} - C H O (i) S n C l_{2} / H C l \leftarrow ------- - (i i) H_{2} O B$
A and B respectively are -

A

Benzoyl chloride and benzonitrile

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B

Benzyl chloride and benzylnitrile

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C

Benzal chloride and benzonitrile

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D

Benzotrichloride and benzonitrile

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Solution

The correct option is A Benzoyl chloride and benzonitrile
When benzoyl chloride reacts with $H_{2}$ in the presence of $P d - B a S O_{4}$ , benzaldehyde will be formed. This reaction is known as Rosenmund's reaction. When benzonitrile reacts with $S n C l_{2} / H C l$ followed by hydrolysis, benzaldehyde will be formed. This reaction is known as Stephen's reaction. Hence the correct answer will be option (a).

Stephen reaction:

Rosenmund reaction:

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