The correct option is D 12.5mA,7.5mA,5mA
As long as the Vin is greater than the zener Voltage 10V, the zener is in breakdown region and hence the voltage across the load remains constant. The series limiting resistance 4kΩ limits the input current.
Current in load IL=102×103=5mA
Voltage drop across the 4kΩ is 60−10=50V
Hence I=504×103=12.5mA
Hence, IZ=I−IL=12.5−5=7.5mA